distance is 1,225757819×10¹⁹ m so 81938502,673796791 AU (±82M AU)
FYI a ship going 10km/s would need 4156h to run 1AU
now let’s put coordinates in k AU instead of m, rounded 3rd number
so from those few example we can deduce wh space is high X, high negative z
Now looking at the map, what is north : basically northest Kspace system is qyzm which is, in position and k AU (-669, 427, 3160) ; while the southest one seems to be lx5k with position (-1000, -278, -3240).
from this we can assume than north is Z>0, becasue it’s the highest normal difference.
I’m tired, I’ll let you do the same for x and y.