If you apply 25% resist three times…
If you apply 20% resist three times…
You get an overall 17% difference.
It’s compounded.
100 damage taken: At 25% resist, you TAKE 75% damage.
75% = 3/4; (3/4)^3 = 27/64; 27/64 = 42% damage TAKEN.
So 100 damage turns in 42 damage if you stack 25% resist modules three times.
Now for 20% resists: At 20% resist you TAKE 80% damage.
80% = 4/5; (4/5)^3 = 64/125; 64/125 = 51% damage TAKEN.
So 100 damage turns in 51 damage if you stack 20% resist modules three times.
Now difference between triple stacked 25’s vs 20’s.
42 vs 51: 42/51 = 82.5%.
100-82.5% = 17.5%
The armor tanker now takes 17.5% more damage in his weakest hole.
I can’t make the math any more clear.
In general a resist mod that does (x/y) resistance results in (y-x)/y damage taken.
The difference between two mods goes according the formula (where s = number of stacks):
((y1-x1)/y1)^s vs. ((y2-x2)/y2)^s
Thence:
- 1 - [ ((y2-x2)/y2)^s)/ ((y1-x1)/y1)^s]*
Is the difference. That’s the calculation we performed for s = 3, x1 =3, y1 =4, x2 =4, y2=5.
@Scoots_Choco
I saw you liked the above post , you like incorrect math?